Mathématiques

Question

Factorisez les expressions suivantes: S= (3x +2)(4x -1)+(8x - 2)(7x - 8) T= (6x + 1)(3 - x) - 36x² + 1 R= (4x + 4)(x - 5) +(3x + 3)(x - 9)

2 Réponse

  • S=(3x+2)(4x-1)+(8x-2)(7x-8)
      =(4x-1)(3x+2+2(7x-8))
      =(4x-1)(17x-14)

    T=(6x+1)(3-x)-36x²+1
      =(6x+1)(3-x)-(6x-1)(6x+1)
      =(6x+1)(3-x-6x+1)
      =(6x+1)(-7x+4)

    R=(4x+4)(x-5)+(3x+3)(x-9)
      =(x+1)(4(x-5)+3(x-9))
      =(x+1)(7x-47)
  • S = (3x + 2)(4x - 1) + (8x - 2)(7x - 8)
    S= (3x + 2)(4X - 1) + 2(4x - 1)(7x - 8)
    S = ( 4x - 1) [ (3x + 2) + 2(7x - 8)]
    S = (4x - 1) [3x + 2 + 14x - 16]
    S = (4x - 1) (17x - 14)

    T = (6x + 1)(3 - x) - 36x² + 1
    T = (6x + 1)(3 - x) - (36x² - 1)                            36x² - 1² =( 6x + 1) (6x - 1)
    T = (6x + 1)(3 - x) - ( 6x + 1)(6x - 1)
    T = (6x + 1) [ (3 - x) - (6x - 1)]
    T = (6x + 1) [ 3 - x - 6x + 1]
    T = (6x + 1) ( - 7x + 4)

    R = (4x + 4)(x - 5) + ( 3x + 3)( x - 9)
    R = 4(x + 1)(x - 5) + 3(x + 1)( x - 9)
    R =  (x + 1) [(x - 5) + 3(x - 9)]
    R =  (x + 1) [ x - 5 + 3x - 27]
    R = (x + 1) (4x - 32) ...........................4x - 32 = 4(x - 8)
    R = 4 (x + 1)(x - 8)

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