Mathématiques

Question

a=(x+3)(7x-5)-(7x-5)2

2 Réponse

  • A=(x+3)(7x-5)-(7x-5)²=(7x-5)(x+3-(7x-5))
    =(7x-5)(x+3-7x+5)
    =(7x-5)(-6x+8)
    =2(7x-5)(-3x+4)
  • Factorisation :

    [tex]A = (x+3)(7x-5)-(7x-5)2[/tex]
    [tex]A = (7x-5) (x+3-7x+5)[/tex]
    [tex]A= (7x-5) (-6x+8)[/tex]
    [tex]A= 2 (7x-5) (-3x + 2)[/tex]

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