Mathématiques

Question

factoriser et reuire les facteurs (y+2)(5y-7)+(y+2)(2y+9) //4-12t+9t2 //4xau carré+28x+49

2 Réponse

  • bonjour,

    (y+2)(5y-7)+(y+2)(2y+9)=
    (y+2)(5y-7+2y+9) =
    (y+2)(7y+2)

    4-12t+9t² =
     a²-2ab+b² =
    (a-b)² =
    (2-3t)²

    4x²+28x+49  =
     a²+2ab+b²=
    (a+b)² =
    (2x+7)²



  • Bonjour , 
    1/ (y+2)(5y-7)+(y+2)(2y+9)
    = (y+2) [(5y-7)+(2y+9)]
    = (y+2) (7y+2)
    2/ 4 - 12t + 9t²
    = 2² - 2 × 3t × 2 + (3t)²
    = (2-3t)²
    3/ 4x² + 28x + 49 
    = (2x)² + 2 × 2x × 7 + 7²
    = (2x+7)²

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