1) (x + 5) – 3 (x+5)^2= 0 svp

(x+5) - 3(x+5)² = 0
(x+5) - 3(x+5)(x+5) = 0
(x+5)(1 - 3(x+5)) = 0
(x+5)(-3x - 14) = 0

x + 5 = 0  --> x = -5
-3x - 14 = 0  --> x = -14/3

bonjour,

(x + 5) – 3 (x+5)^2= 0= 
1(x + 5) – 3 (x+5)^2= 0 (x+5)(1-3x-15) =0
(x+5)(-3x-14) = 0
x=5 =0
x =-5
-3x-14 =0
x = -14/3