aider moi SVP SEULEMENT L'EXERCICE 2

Bonjour,

a)
(x - 1) (2x - 2) + (2x - 2) (5 - 2x)
= (2x - 2) [(x - 1) + (5 - 2x)
= (2x - 2) (x - 1 + 5 - 2x)
= (2x - 2) (- x + 4)

b)
(4 - 3x) (x + 5) - (4 - 3x) (x + 2)
= (4 - 3x) [(x + 5) - (x + 2)]
= (4 - 3x) (x + 5 - x - 2)
= (4 - 3x) (3)
= 3 (4 - 3x)

c)
(2x + 5) (x + 2) - (2x + 5)
= (2x + 5) [(2x + 5) - (x + 2)]
= (2x + 5) (2x + 5 - x - 2)
= (2x + 5) (x + 3)

d)
(x + 1) (3 - 2x) + (3 - 2x)²
= (3 - 2x) [(3 - 2x)+ (x + 1)]
= (3 - 2x) (3 - 2x + x + 1)
= (3 - 2x)  (- x + 4)