Binjour poyvais vous m aidez svp ?

1) developper :

f(x)=2x^2-6x+x-3+6x^2+4x+3x+2

f(x)=8x^2 + 2x - 1

2) factoriser :

f(x)=(2x+1)(x-3+3x+2)
f(x) = (2x+1)(4x-1)

3) a) calculer :

f(0) = 8*(0)^2+2*0-1
f(0) = -1

f(-1/2)=(2*(-1/2)+1)(4*(-1/2)-1)
f(-1/2)=(-1+1)(-2-1)
f(-1/2)=0

f(V2)=8*(V2)^2+2V2-1
f(V2)=8*2+2V2-1
f(V2)=16-1+2V2
f(V2) = 15 + 2V2

b) resoudre :

f(x)=0
(2x+1)(4x-1)=0
2x+1 = 0 et 4x-1 = 0
2x = -1 et 4x = 1
x = -1/2 et x = 1/4

c) resoudre :

f(x) = 8x^2
8x^2 + 2x - 1 = 8x^2
8x^2 - 8x^2 + 2x - 1 = 0
2x - 1 = 0
2x = 1
x = 1/2