Factoriser 4x②-20x+25 16-9y② 49-(3x+1)② (x+3)(x-9)-(x+3)②
Mathématiques
Anonyme
Question
Factoriser
4x②-20x+25
16-9y②
49-(3x+1)②
(x+3)(x-9)-(x+3)②
4x②-20x+25
16-9y②
49-(3x+1)②
(x+3)(x-9)-(x+3)②
1 Réponse
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1. Réponse Anonyme
Bonsoir ,
4x²-20x+25
= (2x)² - 2 × 2x × 5 + 5²
= (2x+5)²
16-9y²
= 4² - (3y)²
= (4-3y) (4+3y)
49 - (3x+1)²
= 7² - (3x+1)²
= [ 7 -(3x+1) ] [ 7 + (3x+1) ]
= [ 7 - 3x - 1 ] [ 7 + 3x + 1 ]
= ( 6 - 3x ) ( 8 + 3x )
(x+3)(x-9) - (x+3)²
= (x+3) [ ( x-9) - (x+3) ]
= (x+3) [ x-9 - x - 3 ]
= -12 (x+3)