On pose A= (2x-5)² - (2x-5) (4x-6) Factoriser A
Mathématiques
assia080601
Question
On pose A= (2x-5)² - (2x-5) (4x-6) Factoriser A
2 Réponse
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1. Réponse Lemuel6
A= (2x-5)² - (2x-5) (4x-6)
= (2x-5)² - (2x-5) 2 (2x-3)
= (2x-5) [2x-5- 2(2x-3)]
= (2x-5) (2x-5-4x+6)
= (2x-5) (-2x+1) -
2. Réponse hajarri2002
A= (2x-5)² - (2x-5) (4x-6) =(2x-5)(2x-5-(4x-6)) . =(2x-5)(2x-5-4x+6) . =(2x-5)(1-2x)